`|veca-vecb|=|veca+vecb|` if if and only if....

Prove that (veca+ vecb)*( veca+ vecb)=|veca|^2+| vecb|^2 , if and only if veca , vecb are perpendicular, given veca!= vec0, vecb!= vec0

Prove that (veca+vecb) cdot (veca+vecb) = |veca|^2 + |vecb|^2 , if and only if veca, vecb are perpendicular, given veca ne vec0, vecb ne vec0 .

For non-zero vectors veca, vecb and vecc , |(veca xx vecb) .vecc| = |veca||vecb||vecc| holds if and only if

For non-zero vectors veca, vecb and vecc , |(veca xx vecb) .vecc| = |veca||vecb||vecc| holds if and only if

For non-zero vectors veca, vecb and vecc , |(veca xx vecb) .vecc = |veca||vecb||vecc| holds if and only if

For non-zero vectors veca, vecb and vecc , |(veca xx vecb) .vecc = |veca||vecb||vecc| holds if and only if

|veca| = |vecb| = veca = vecb .

Prove that (veca+vecb)*(veca+vecb)=|veca|^(2)+|vecb|^(2) , if and only if veca,vecb are perpendicular , given vecanevec0,vecbnevec0 .

Prove that (veca+vecb)*(veca+vecb)=|veca|^(2)+|vecb|^(2) , if and only if veca,vecb are perpendicular , given vecanevec0,vecbnevec0 . Choose the correct answer in Exercises 16 to 19.