A `6 kg` blocks is kept over a rough surface with coefficients of friction `mu_(s)=0.6` and `mu_(k)=0.4` as shown in figure. A time varying force `F=4t` ( `F` in newton and `t` in second) is applied on the block as shown. Find the acceleration of block at `t=5 sec`. ( Taking `g=10 m//s^(2)`)

A 6 kg block is kept over a rough surface with coefficient of friction mu_(s) = 0.6 and mu_(k) = 0.4 as shown in figure.A time varying force F = 4t (F in newton and t in second) is applied on the block as shown. Plot a graph between acceleration of block and time (g = 10 m//s^(2))

A 6 kg block is kept over a rough surface with coefficient of friction mu_(s) = 0.6 and mu_(k) = 0.4 as shown in figure.A time varying force F = 4t (F in newton and t in second) is applied on the block as shown. Plot a graph between acceleration of block and time (g = 10 m//s^(2))

A 2 kg block is kept over a ground with coefficient of friction mu = 0.8 as shown in figure.A time varying force F = 2t (F in newton and t in second) is applied on the block. Plot a graph between acceleration of block versus time (g = 10 m//s^(2))

A 2 kg block is kept over a ground with coefficient of friction mu = 0.8 as shown in figure. A time varying force F = 2t (F in newton and t in second) is applied on the block. Plot a graph between acceleration of block versus time (g = 10 m//s^(2))

A block of mass 8 kg is kept on a rough floor. The coefficients of friction are mu_(s) = 0.5 and mu_(k) = 0.4 . Force F_(1) = 15 N and F_(2) = 20 N are applied on the block as shown. (a) Find the magnitude and the direction of friction force . (b) If F_(1) = 30 N , F_(2) = 40 N , find the acceleration of the block.

In the given figure, the blocks of mass 2kg and 3kg are placed one over the other as shown. The surface are rough with coefficient of friction mu_(1)=0.2, mu_(2)=0.06 . A force F=0.5t (where 't' in sec) is applied on upper block in the direction shown. Based on above data answers the following questions. (g = 10 m//sec^(2)) The frictional force acting between 3 kg block and ground w.r.t. time will vary as :

In the given figure, the blocks of mass 2kg and 3kg are placed one over the other as shown. The surface are rough with coefficient of friction mu_(1)=0.2, mu_(2)=0.06 . A force F=0.5t (where 't' in sec) is applied on upper block in the direction shown. Based on above data answers the following questions. (g = 10 m//sec^(2)) The frictional force acting between the blocks at t=10 sec is

In the given figure, the blocks of mass 2kg and 3kg are placed one over the other as shown. The surface are rough with coefficient of friction mu_(1)=0.2, mu_(2)=0.06 . A force F=0.5t (where 't' in sec) is applied on upper block in the direction shown. Based on above data answers the following questions. (g = 10 m//sec^(2)) The acceleration time graph for 4 kg block is :

In the given figure, the blocks of mass 2kg and 3kg are placed one over the other as shown. The surface are rough with coefficient of friction mu_(1)=0.2, mu_(2)=0.06 . A force F=0.5t (where 't' in sec) is applied on upper block in the direction shown. Based on above data answers the following questions. (g = 10 m//sec^(2)) The frictional force acting between the two blocks at t=9 sec

In the given figure, the blocks of mass 2 kg and 3 kg are placed one over the other as shown. The surface are rough with coefficient of friction mu_(1)=0.2, mu_(2)=0.06 . A force F=0.5t ( where 't' "in" sec ) is applied on upper block in the direction shown. Based on above data answer the following questions. ( g= 10m//sec^(2)) The frictional force acting between the two blocks at t=8 sec .