A `6 kg` block is kept over a rough surface with coefficient of friction `mu_(s) = 0.6` and `mu_(k) = 0.4` as shown in figure.A time varying force `F = 4t (F` in newton and `t` in second) is applied on the block as shown. Plot a graph between acceleration of block and time `(g = 10 m//s^(2))`

A 6 kg blocks is kept over a rough surface with coefficients of friction mu_(s)=0.6 and mu_(k)=0.4 as shown in figure. A time varying force F=4t ( F in newton and t in second) is applied on the block as shown. Find the acceleration of block at t=5 sec . ( Taking g=10 m//s^(2) )

A 2 kg block is kept over a ground with coefficient of friction mu = 0.8 as shown in figure.A time varying force F = 2t (F in newton and t in second) is applied on the block. Plot a graph between acceleration of block versus time (g = 10 m//s^(2))

A 2 kg block is kept over a ground with coefficient of friction mu = 0.8 as shown in figure. A time varying force F = 2t (F in newton and t in second) is applied on the block. Plot a graph between acceleration of block versus time (g = 10 m//s^(2))

In the given diagram, the block of mass 2 kg and 3 kg are placed one over the other . The contact surfaces are rough with coefficient of friction mu_(1) = 0.2, mu_92) = 0.06) . A force F= 1/2t N ( where t is in second ) is applied on upper block in the direction ( Given that g = 10m//s^(2)) The acceleration time graph for 4 kg block is : Friction force acting between the two blocks at t=8 s

In the given figure, the blocks of mass 2kg and 3kg are placed one over the other as shown. The surface are rough with coefficient of friction mu_(1)=0.2, mu_(2)=0.06 . A force F=0.5t (where 't' in sec) is applied on upper block in the direction shown. Based on above data answers the following questions. (g = 10 m//sec^(2)) The frictional force acting between 3 kg block and ground w.r.t. time will vary as :

In the given figure, the blocks of mass 2kg and 3kg are placed one over the other as shown. The surface are rough with coefficient of friction mu_(1)=0.2, mu_(2)=0.06 . A force F=0.5t (where 't' in sec) is applied on upper block in the direction shown. Based on above data answers the following questions. (g = 10 m//sec^(2)) The acceleration time graph for 4 kg block is :

In the given diagram, the block of mass 2 kg and 3 kg are placed one over the other . The contact surfaces are rough with coefficient of friction mu_(1) = 0.2, mu_92) = 0.06) . A force F= 1/2t N ( where t is in second ) is applied on upper block in the direction ( Given that g = 10m//s^(2)) The acceleration time graph for 4 kg block is : The relative slipping between the blocks occurs at t =

In the given figure, the blocks of mass 2kg and 3kg are placed one over the other as shown. The surface are rough with coefficient of friction mu_(1)=0.2, mu_(2)=0.06 . A force F=0.5t (where 't' in sec) is applied on upper block in the direction shown. Based on above data answers the following questions. (g = 10 m//sec^(2)) The friction force between the blocks and time graph is :

In the given figure, the blocks of mass 2kg and 3kg are placed one over the other as shown. The surface are rough with coefficient of friction mu_(1)=0.2, mu_(2)=0.06 . A force F=0.5t (where 't' in sec) is applied on upper block in the direction shown. Based on above data answers the following questions. (g = 10 m//sec^(2)) The frictional force acting between the blocks at t=10 sec is

In the given figure, the blocks of mass 2 kg and 3 kg are placed one over the other as shown. The surface are rough with coefficient of friction mu_(1)=0.2, mu_(2)=0.06 . A force F=0.5t ( where 't' "in" sec ) is applied on upper block in the direction shown. Based on above data answer the following questions. ( g= 10m//sec^(2)) The motion of blocks 2 kg and 3 kg will begin at time t = -, - respectively