हल कीजिए :
`5x+7y-31 =0`
` 7x-9y +13=0`

6x - 5y - 16 = 0 , 7x - 13 y + 10 = 0 .

5x + 2y = 31 3x + 7y = 36

Solve the system: x + y - 2z = 0, 2x - 3y + z = 0, 3x - 7y + 10z = 0, 6x - 9y + 10z = 0.

5x - 4y + 8 = 0 7x + 6y - 9= 0

The equation of bisector of angle which contains the origin between the straight lines 4x-3y-6=0 and 5x+12y+9=0 is: a.7x+9y+3=0 b.7x+9y-3=0 c.7x-9y+3=0 d.none of these

Solve, using cross - multiplication : 4x - 7y + 28 = 0 and -7x + 5y + 9 = 0 .

Distance between the lines 5x + 3y-7 = 0 and 15x +9y + 14 = 0 is

Solve, using cross - multiplication : 6x + 7y - 11 = 0 5x + 2y = 13

Two consecutive sides of a parallelogram are 4x+5y=0a d n7x+2y=0. If the equation of one diagonal is 11 x+7y=9, Equation of other diagonal : (A) 11x + 7y =0 (B) 3x - 5y + 5 = 0 (C) 7x + 11y = 0 (D) 3x + 5y + 5 =0