Consider `f(theta)=|[tan theta,cos theta,sin theta],[cos theta,sin theta,tan theta],[sin theta,tan theta,cos theta]|` then `f((pi)/(4))+f(0) = ?`

If 3cos theta-4sin theta=2cos theta+sin theta, find tan theta.

If 3cos theta-4sin theta=2cos theta+sin theta then find tan theta

If f(theta)=|[cos^(2)theta,cos theta sin theta,-sin theta],[cos theta sin theta,sin^(2)theta,cos theta],[sin theta,-cos theta,0]| , then f((pi)/(12))

if sin theta=cos theta then tan theta=

(sin theta+sin2 theta)/(1+cos theta+cos2 theta)=tan theta=sin theta*sec theta

(sin theta+sin2 theta)/(1+cos theta+cos2 theta)=tan theta

(sin theta+sin2 theta)/(1+cos theta+cos2 theta)=tan theta

(cos6 theta-cos4 theta)/(sin6 theta+sin4 theta)=-tan theta

If f(theta)=|(cos^(2)theta ,cos theta sin theta, -sin theta),(cos theta sin theta, sin^(2)theta,cos theta),(sin theta,-cos theta,0)| then, f((pi)/(6))+f((pi)/(3))+f((pi)/(2))+f((2pi)/(3))+f((5pi)/(6))+f(pi)+……+f((53pi)/(6)) is equal to

(cos theta-sin theta) / (cos theta + sin theta) = sec2 theta-tan2 theta