The product of the perpendicular distances from the point (-2,3) to the lines `x^(2)-y^(2)+2x+1=0` is

The product of the perpendiculars drawn from the point (1,2) to the pair of lines x^(2)+4xy+y^(2)=0 is

The distance of the point (-2,3) from the line x-y=5 is

The product of the perpendiculars drawn from (2,-1) to the pair of lines x^(2)-3xy+2y^(2)=0 is

The product of the length of the perpendiculars drawn from the point (1,1) to the pair of lines x^(2)+xy-6y^(2)=0

Find the coordinates of the foot of the perpendicular and the perpendicular distance from the point P(3,2,1) to the plane 2x-y+z+1=0 .