Find the curve such that the area of the trapezium formed by the co-ordinate axes, ordinate of an arbitrary point & the tangent at this point equals half the square of its abscissa.

Find the curve such that the area of the trapezium formed by the co-ordinate axes, ordinate of an arbitrary point & the tangent at this point equals half the square of its abscissa.

A curve is such that the area of the region bounded by the co-ordinate axes,the curve delta the coordinate of any point on it is equal to the cube of that ordinate.The curve represents

The equation of the curve,passing through (2, 5) and having the area of triangle formed by the X-axis,the ordinate of a point on the curve and the tangent at the point 5 sq.units as

Find the equation of the curve which is such that the area of the rectangle constructed on the abscissa of and the initial ordinate of the tangent at this point is a constanta =a^(2)

Find the co ordinates of the feet of perpendiuclars from the point (a,b,c) on the co ordinate axes

Show that equation to the curve such that the y-intercept cut off by the tangent at an arbitrary point is proportional to the square of the ordinate of the point of tangency is of the form a/x+b/y=1 .

Show that equation to the curve such that the y-intercept cut off by the tangent at an arbitrary point is proportional to the square of the ordinate of the point of tangency is of the form a/x+b/y=1 .