If `A= [a_(ij)] _(nxxn)` and f is a function, we define
`f (A) = [f(a_(ij))] _(nxxn)."Let"A = [[pi/1-theta,theta],[-theta,pi/2-theta]]` then

If A= [a_(ij)] _(nxxn) and f is a function, we define f (A) = [f(a_(ij))] _(nxxn)."Let"A = [[pi/2-theta,theta],[-theta,pi/2-theta]] then

If A=((a_(i j)))_(nxxn) and f is a function, we define f(A)=((f(a_(i j))))_(nxxn ') Let A=(pi//2-thetatheta-thetapi//2-theta) . Then sinA is invertible b. sinA=cos A c. sinA is orthogonal d. sin(2A)=2AsinA cos A

Let f(theta)=sin theta(sin theta+sin3 theta)* then

Let A=[a_(ij)]_(nxxn) n is odd. Then det ((A-A^(T))^(2009)) is equal to

Let f(theta)=sintheta(sintheta+sin3theta).Then, f(theta)

Let f(theta)=sin theta(sin theta +sin 3 theta). " Then " f(theta)

The range of the function f (theta) =(sin theta)/( theta ) + (theta)/(tan theta) , theta in (0, (pi)/(2)) is equal to :

If min and max value of the function f:[pi/4,pi/2] to R, f(theta)=|[-sin^2theta,-1-sin^2theta,1],[-cos^2theta,-1-sin^2theta,1],[12,-4,0]| are m and M . Find the ordered pair (m,M) .

If f:[0,(pi)/(2))rarr R is defined as f(theta)=det[[1,tan theta,1-tan theta,1,tan theta-1,-tan theta,1]] Then,the range of f is