`"White" "vitrol "overset(100^(@)C)underset(Delta)rarrXoverset(250^(@)C)(rightarrow)Y` . If loss in weight in the first step is `A` gm and that of in second step is `B` gm,then `(B)/(A)=`

White vitriol overset(100^(@)C)underset(Delta)rarrXoverset(250^(@)C)rarrY . If loss in weight in the first step is 'A' gm and that of in second step is 'B' gm , then (B)/(A)=

4P_(4)O_(6) overset(Delta)underset(250^(@)C)rarr 3X +P_(4) then X =______

C_(6) H_(5)CH_(3)overset((1)CrO_(2)Cl_(2)//CS_(2))underset(H_(3)O^(+))rightarrow (A) overset(OH^(-))rightarrow (B) The Conversition of A to B is called as

In the reaction 2 CH_(3)underset(O)underset(||)(C)CH_(3)overset("Base")(rarr)A overset(Delta)(rarr)B the product B is :

underset(Zn)overset(O_(3)(1"mole"))(rarr) "(A)" overset(Conc.KOH)(rarr) (B) underset(Delta)overset(H^(+))(rarr) (C ), Product (C ) is

A+B overset(dilOH^(-))rightarrow Ph -CH =CH-underset(CH_(3))underset(|)C=O identfy A&B in the above reaction

CH_(3)-C -= N +underset("(excess)")(H_(2)O) overset(H^(+))to A underset(Delta)overset(NaOH+CaO)to B B is ?

The mechanism of SN1 reaction is given below : CH_(3)-underset(CH_(3)) underset(|) overset(CH_(3)) overset(|)C-Broverset("step-1")toCH_(3)-underset(CH_(3)) underset(|)overset(o+)C-CH_(3)+ overset(o+)(Br) overset(Nu)underset("step-II")to CH_(3)- underset(CH_(3)) underset(|)overset(CH_(3))overset(|)C-Nu Given answer of the following questions on the basis of the machanism given below. Which statement is NOT correct ?