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In this figure,the force (in N ) on mas...

In this figure,the force (in N ) on mass 5kg that should be applied,so that it just won't slip is (Given that car is moving with constant acceleration `(a=5m/s^(2),mu=0.4))`

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Passage X) A 2kg block hangs without vibrating at the bottom end of a spring with a force constant of 400 N/m. The top end of the spring is attached to the ceiling of an elevator car. The car is rising with an upward acceleration of 5m/ s^(2) when the accleration suddenly ceases at t=0 and the car moves upward with constant speed. (g=10m/ s^(2) ) What is the angular frequency of oscillation of the block after the acceleration ceases?

Passage X) A 2kg block hangs without vibrating at the bottom end of a spring with a force constant of 400 N/m. The top end of the spring is attached to the ceiling of an elevator car. The car is rising with an upward acceleration of 5m/ s^(2) when the accleration suddenly ceases at t=0 and the car moves upward with constant speed. (g=10m/ s^(2) ) The amplitude of the osciallations is

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A 2kg block hangs without vibrating at the bottom end of a spring with a force constant of 400 N//m . The top end of the spring is attached to the ceiling of an elevator car. The car is rising with an upward acceleration of 5 m//s^(2) when the acceleration suddenly ceases at time t = 0 and the car moves upward with constant speed (g = 10 m//s^(2)) What is the angular frequencyof the block after the acceleration ceases ?

A 2kg block hangs without vibrating at the bottom end of a spring with a force constant of 400 N//m . The top end of the spring is attached to the ceiling of an elevator car. The car is rising with an upward acceleration of 5 m//s^(2) when the acceleration suddenly ceases at time t = 0 and the car moves upward with constant speed (g = 10 m//s^(2) The amplitude of the oscillation is

In the given figure, the blocks of mass 2 kg and 3 kg are placed one over the other as shown. The surface are rough with coefficient of friction mu_(1)=0.2, mu_(2)=0.06 . A force F=0.5t ( where 't' "in" sec ) is applied on upper block in the direction shown. Based on above data answer the following questions. ( g= 10m//sec^(2)) The relative slipping between the blocks occurs at t=

As shown in figure, if we apply a horizontal force F on the block, find the maximum force F (in N ) that can be applied so that block does not slide up. ( "Given" theta=45^(@),g=10m//sec^(2), m=1/5kg,mu=1/2)

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In the given figure, the blocks of mass 2kg and 3kg are placed one over the other as shown. The surface are rough with coefficient of friction mu_(1)=0.2, mu_(2)=0.06 . A force F=0.5t (where 't' in sec) is applied on upper block in the direction shown. Based on above data answers the following questions. (g = 10 m//sec^(2)) The acceleration time graph for 4 kg block is :