E is any point on median `AD` of `/_ABC` .If `ar(Delta ABE)=10cm^(2)` then `ar(Delta ACE)` is

E is any point on median AD of AABC If ar( triangleABE ) = 10 cm then ar(triangleACE ) is

In the adjoining figure,E is a point on the median AD of a Delta ABC. Show that ar (Delta ABE)=(Delta ACE)

In the given figure ar (Delta ABC)=" ar "(Delta ADE) . AC is the median of Delta ADE . If ar (ACE) =14 cm^(2)" then ar "(Delta ABC) = ?

In the figure, E is any point on median AD of a triangleABC . Show that ar( triangleABE )= ar( triangleACE ).

In Fig.9.23,E is any point on median AD of a Delta ABC Show that ar (ABE)=ar(ACE)

D is any point on side AC of a Delta ABC with AB= AC .then

In an equilateral Delta ABC, D is the midpoint of AB and E is the midpoint of AC. Then, ar (Delta ABC) : ar (Delta ADE)=?

ABC, (DE)/(AB)=2:3 and ar(Delta DEF)=44 sq.units then ar ( DeltaABC) is

In a trapezium ABCD , it is given that AB||CD and AB= 2CD . Its diagonals AC and BD intersect at the point O such that ar (Delta AOB)=84 cm^(2) . Find ar (Delta COD)

D is the mid-point of side BC of Delta ABC and E is the mid-point of BO. If O is the mid-point of AE, then ar( Delta BOE) = 1/k ar( Delta ABC). Then k equals