A particle is moving such that its position coordinates (x,y) are (2m,3m) at time t=0,(13m,14m) at time `t=5s` .Average velocity vector from t =0 to t=5s

A particle is moving such that its position coordinates (x, y) are (2m, 3m) at time t=0, (6m, 7m) at time t=2 s , and (13 m, 14m) at time t=5 s . Average velocity vector (vec(V)_(av)) from t=0 to t=5 s is

A particle is moving along x-axis such that its velocity varies with time according to v=(3m//s^(2))t-(2m//s^(3))t^(2) . Find the velocity at t = 1 s and average velocity of the particle for the interval t = 0 to t = 5 s.

A particle moves in a straight line. Its position ( in m) as function of time is given by x = (at^2 + b) What is the average velocity in time interval t = 3s to t = 5s in ms^(-1) . (where a and b are constants and a = 1ms^(-2), b = 1m ).

A particle moves in a straight line, its position (in m) as function of time is given by x = (at^2 + b) . What is average velocity in time interval t = 3 sec to t = 5 sec ? (Where a and b are constant and a = 1 m//s^2, b = 1 m .)

A particle is moving in XY plane such that its velocity in x-direction remains constant at 5 m//s and its velocity in y-direction varies with time as v = 3 t m//s , where t is time in seconds. Find :

A particle is projected with speed 100m/s at angle theta=60^(@) with the horizontal at time t=0" . At time 't' the velocity vector of the particle becomes perpendicular to the direction of velocity of projection.Its tangential acceleration at time 't' is (g =10m/s^(2))

A particle moves along X-axis in such a way that its coordinate X varies with time t according to the equation x = (2-5t +6t^(2))m . The initial velocity of the particle is

A particle is moving in a straight line. Its displacement at time t is given by s(I n m)=4t^(2)+2t , then its velocity and acceleration at time t=(1)/(2) second are

Position of a particle at any instant is given by x = 3t^(2)+1 , where x is in m and t in sec. Its average velocity in the time interval t = 2 sec to t = 3 sec will be :