If a simple harmonic motion is represented by `(d^(2)x)/(dt^(2)) + alphax = 0`, its time period is :

If a simple harmonic motion is erpresented by (d^(2)x)/(dt^(2))+ax=0 , its time period is.

The equation of a simple harmonic motion of a particle is (d^(2)x)/(dt^(2)) + 0.2 (dx)/(dt) + 36x = 0 . Its time period is approximately

A sinple harmonic motion is represented by (d^2x)/(dt^2)+kx=0 , where k is a constant of the motion. Find its time period.

A particle executes simple harmonic motion according to equation 4(d^(2)x)/(dt^(2))+320x=0 . Its time period of oscillation is :-

A particle is executing a linear S.H.M. and its differential equation is (d^(2)x)/(dt^(2))+ alpha x=0 . Its time period of motion is

For a particle performing SHM , equation of motion is given as (d^(2))/(dt^(2)) + 4x = 0 . Find the time period

A simple harmonic motion is represented by x = 12 sin (10 t + 0.6) Find out the maximum acceleration, if displacement is measured in metres and time in seconds.

A simple harmonic motion is represented by : y=59sin3pit+sqrt(3)cos3pit)cm The amplitude and time period of the motion by :

If the displacement (x) and velocity (v) of a particle executing simple harmonic motion are related through the expression 4v^2=25-x^2 , then its time period is given by

Displacement 'x' of a simple harmonic oscillator varies with time, according to the differential equation (d^(2)x//dt^(2))+4x=0 . Then its time period is