If `tan(x/2)=cosec x-sin x" ` then `(1+sec^(2)(x)/(2))^(2)=`

If tan(x/2)=cosec x-sin x , then tan^(2)(x/2) is equal to

int (sec^(2)x)/(cosec^(2)x) dx

Solve : 1+2cosec x=-("sec"^(2)(x)/(2))/(2)

which one the following does not reduce to sin x for every x ,where defiened,is (A)(tan x)/(sec x)(B)(sin x)/(sec^(2)x-tan^(2)x) (C) (sin^(2)x sec x)/(tan x)

sec theta-cos theta=x and cosec theta-sin theta=y then x^2 y^2 (x^2+y^2+3)=

(cosec x-sin x)(sec x-cos x)(tan x+cot x)=1

If: 2.tan^(-1)(cos x) = tan^(-1)(cosec^(2)x) , then: x=

(cosec x-sin x)(sec x-cos x)(tan x+cot x)