The lines `(x-1)/2=y/- 1=z/2 and x-y+z-2=0=lambdax+3z+5` are coplanar for `lambda`

The lines (x-1)/(2)=(y)/(-1)=(z)/(2) and x-y+z-2=0=lambda x+3z+5 are coplanar for lambda

If the lines (x-1)/(2)=(y)/(-1)=(z)/(2) and x-y+z-2=0=lambdax+3z+5 are coplanar, then the value of 7lambda is equal to

The lines (x-1)/1=(y+1)/-1=z/2 and x/2=(y-1)/-2=(z-1)/lambda are

Statement 1: The lines (x-1)/1=y/(-1)=(z+1)/1 and (x-2)/2=(y+1)/2=z/3 are coplanar and the equation of the plnae containing them is 5x+2y-3z-8=0 Statement 2: The line (x-2)/1=(y+1)/2=z/3 is perpendicular to the plane 3x+5y+9z-8=0 and parallel to the plane x+y-z=0

The lines x = ay -1 = z -2 and z = 3 y - 2 = bz-2, (ab ne 0) are coplanar, if

If the lines (x+4)/(3)=(y+6)/(5)=(z-1)/(-2) and 3x-2y+z+5=0=2x+3y+4z-k are coplanar,then k=(a)-4(2)3(3)2(4)4 (5)1

The lines x+y+z-3=0=2x-y+5z-6 and x-y-z+1=0=2x+3y+7 are coplanar then k equals

The non zero value of a for which the lines 2x-y+3z+4=0=ax+y-z+2 and x-3y+z=0=x+2y+z+1 are co-planar is :