For an "AC" circuit,current and voltage are respectively i=2sin(250 pi t)ampere and V=10sin(250 pi t+(pi)/(3))" volts.Find the instantaneous power (in watt) drawn from the source at t=(2)/(3)ms

In an ac circuit the instantaneous values of current and applied voltage are respectively i=2(Amp) sin (250pis^(-1)t and epsi =(10V) sin [(250pis^(-1))t+(pi)/(3) , Find the instantaneous power drawn from the source at t=(2)/(3)ms and its average value.

The instantaneous values of alternating current and voltages in a circuit are given as [i=(1)/(sqrt(2))sin(100 pi t) ampere e=(1)/(sqrt(2))sin(100 pi t+pi/3) Volt.The average power in Watts consumed in the circuit is

In a circuit, the instantaneous values of alternating current and voltages in a circuit is given by I = (12)/(sqrt2) sin (100 pi t) A and E = (1)/(sqrt2) sin (100 pi t + (pi)/(3)) V . The average power in watts consumed in the circui is

In an circuit, V and I are given by V=150sin(150t) V and I =150sin(150t+(pi)/(3))A . The power dissipated in the circuit is

In an AC circuit the instantaneous values of emf and current are e=200sin30t volt and i=2sin(300t+(pi)/(3)) amp The average power consumed (in watts) is

Voltage and current in an ac circuit are given by V=5 sin (100 pi t-pi/6) and I=4 sin (100 pi t+pi/6)

In an A.C. circuit , e and I are given by, e=100 sin (100t) volt, I=100sin(100t+(pi)/(3))mA . The power dissipated in circuit is

In an AC circuit, the instantaneous values of e.m.f and current are e=200sin314t volt and i=sin(314t+(pi)/3) ampere. The average power consumed in watt is