If one diagonal of a square is the portion of the line`(x)/a+(y)/b=1` intercepted by the axes, then the extremities of the other diagonal of the square are

One diagonal of a square is the portion of the line 7x+5y=35 intercepted by the axes. Obtain the extremities of the other diagonal.

One of the diagonals of a square is the portion of the line (x)/(2)+(y)/(3)=2 intercepted between the axes.Then the extremities of the other diagonal are: (5,5),(-1,1)(b)(0,0),(4,6)(0,0),(-1,1)(d)(5,5),4,6)

One diagonal of a square is the portion of the line sqrt(3)x+y=2sqrt(3) intercepted by the axes. Obtain the extremities of the other diagonal is : (A) (1+sqrt(3), -1 + sqrt(3)) (B) (1+sqrt(3), 1+sqrt(3) ) (C) (1-sqrt(3), -1+sqrt(3)) (D) (1-sqrt(3), 1+sqrt(3))

One diagonal of a square is the portion of x-axis intercepted by the circle x^2+y^2-4x+6y-12=0 The extremity of the other diagonal is

Prove that the diagonals of a square are equal.

A square is constructed on the portion of x+y=5, which is intercepted between the axes on the side of the line away from origin. The equations to the diagonals of the square are

If the length of a diagonal of a square is a+b then the area of the square is