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The position x of a particle varies with time t as x=at^(2)-bt^(3) .The acceleration of the particle will be zero at time t equal to

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The position x of a particle varies with time t as x=At^(2)-Bt^(3) .the acceleration at time t of the particle will be equal to zero

The position "x" of a particle varies with time (t) as x=At^(2)-Bt^(3)" .the acceleration at time t of the particle will be equal to zero

Knowledge Check

  • The position x of a particle varies with time t as x=at^(2)-bt^(3) . The acceleration at time t of the particle will be equal to zero, where (t) is equal to .

    A
    `(2a)/(3b)`
    B
    `(a)/(b)`
    C
    `(a)/(3b)`
    D
    zero
  • The position x of a particle with time, (t) as x=at^(2)-bt^(3) . The acceleration will be zero at time t equal to

    A
    `(a)/(3b)`
    B
    Zero
    C
    `(2a)/(3b)`
    D
    `(a)/(b)`
  • The position x of a body is defined by equation x = Pt^(2)- Q t^(3) . The acceleration of the particle will be zero at time equal to

    A
    `(P)/(Q)`
    B
    `(Q)/(P)`
    C
    `(P)/(3Q)`
    D
    `(3P)/(Q)`
  • Similar Questions

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    The position "x" of a particle varies with time "(t)" as "x=at^(2)-bt^(3)". The Acceleration at time t of the particle will be equal to zero, where "t" is equal to

    The displacement x of a particle varies with time t as x=4t^(2)-15t+25 Find the position, velocity and acceleration of the particle at t=0. When will the velocity of the particle become zero? Can we call the motion of the particle as one with uniform acceleration ?

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