If the equation `px^(3)+3qx^(2)y+3rxy^(2)+sy^(3)=0` `(p,q,r,s!=0)` represents three coincident lines,then (A) `(p)/(q)=(q)/(r)=(r)/(s)` (B) `pr=qs` (C) `q=s` (D) `p=r`

If the equation px^(3)+3qx^(2)y+3rxy^(2)+sy^(3)=0 and (p,q,r,s!=0) represents three coincident lines,then

If p^(a)=q^(b)=r^(c)=s^(d) and p,q,r,s are in G.P then a,b,c,d are in

If p,q,r,s in R, then equaton (x^(2)+px+3q)(-x^(2)+rx+q)(-x^(2)+sx-2q)=0 has

find the condition that px^(3) + qx^(2) +rx +s=0 has exactly one real roots, where p ,q ,r,s,in R

If p,q,r,s are proportional then ((p-q)(p-r))/(p)=

If the equations px^(2)+qx+r=0 and rx^(2)+qx+p=0 have a negative common root then the value of (p-q+r)=

If px^(3)+qx^(2)+rx+s is exactly divisible by x^(2)-1 , then which of the following is /are necessarily true ? (A) p = r )B) q = s (C ) p =- r (D) q =- s

The solution of equation (p+q-x)/(r)+(q+r-x)/(p)+(r+p-x)/(q)+(3x)/(p+q+r)=0 is

If alpha,beta are the roots of the equation x^(2)+px-r=0 and (alpha)/(3),3 beta are the roots of the equation x^(2)+qx-r=0, then r equals (i)((3)/(8))(p-3q)(3p+q)(ii)((3)/(8))(3p-q)(3p+q)(iii)((3)/(64))(q-3p)(p-3p)(iv)((3)/(64))(p-q)(q-3p)