Let `A B C D` be a p[arallelogram whose diagonals intersect at `P` and let `O` be the origin. Then prove that ` vec O A+ vec O B+ vec O C+ vec O D=4 vec O Pdot`

Let ABCD be a plarallelogram whose diagonals intersect at P and let O be the origin.Then prove that vec OA+vec OB+vec OC+vec OD=4vec OP

Let ABCD be a parallelogram whose diagonals intersect at P and let O be the origin. What is vec(OA) + vec(OB) + vec(OC ) + vec(OD) equal to

If ABCD is a rhombus whose diagonals cut at the origin O, then proved that vec OA+vec OB+vec OC+vec OD+vec O

ABCD is parallelogram and P is the point of intersection of its diagonals.If O is the origin of reference,show that vec OA+vec OB+vec OC+vec OD=4vec OP

A B C D is a parallelogram whose diagonals intersect at Odot If P is any point on B O , prove that: a r\ ( A D O)=A R\ ( C D O) a r\ (\ A B P)=\ a r\ (\ C B P)

If O is a point in space, A B C is a triangle and D , E , F are the mid-points of the sides B C ,C A and A B respectively of the triangle, prove that vec O A + vec O B+ vec O C= vec O D+ vec O E+ vec O Fdot

If vec a + vec b + vec c = o, prove that vec a xxvec b = vec b xxvec c = vec c xxvec a

Let O be an interior point of Delta ABC such that 2vec OA+5vec OB+10vec OC=vec 0

If O is the circumcentre,G is the centroid and O' is orthocentre or triangle ABC then prove that: vec OA+vec OB+vec OC=vec OO

If O is the circumcentre and P the orthocentre ( of Delta ABC, prove that )/(OA)+vec OB+vec OC=vec OP