The inverse of a bijection is unique

The inverse of a bijection is also a bijection

Show that the inverse of a bijective function is unique.

Show that the inverse of a bijective is also a bijection.

Let S = {1, 2, 3}. Determine whether the functions f:S rarr S defined as below have inverses. Find f^(-1) , if it exists. Note : Here we accept that inverse at function is unique. f = {(1, 2), (2, 1), (3, 1)}

Let S = {1, 2, 3}. Determine whether the functions f:S rarr S defined as below have inverses. Find f^(-1) , if it exists. Note : Here we accept that inverse at function is unique. f = {(1, 1), (2, 2), (3, 3)}

Let y = g(x) be the inverse of a bijective mapping f : R rarr R f(x) = 3x^(3) + 2x . The area bounded by graph of g(x), the x-axis and the ordinate at x = 5 is

Prove that, the inverse of a given square matrix, if its exists, is unique.

A function f is have inverse it should be a bijection

The composition of two bijections is a bijection

Let * be an associative binary operation on a set S with the identity element e in S. Then. the inverse of an invertible element is unique.