A particle is moving along `x`-axis with constant acceleration. At `t=0`, the particle is at `x=3m` and `(dx)/(dt)=+4m//s`. The maximum value of `x` co-ordiante of the particle is observed 2 seconds later. Starting from `t=0` sec, after what time, particle reaches its initial position again?

Position of particle moving along x-axis is given by x=2t^(3)-4t+3 Initial position of the particle is

A particle is moving along the x-axis whose acceleration is given by a= 3x-4 , where x is the location of the particle. At t = 0, the particle is at rest at x = 4//3m . The distance travelled by the particles in 5 s is

A particle is moving along the x-axis whose acceleration is given by a= 3x-4 , where x is the location of the particle. At t = 0, the particle is at rest at x = 4//3m . The distance travelled by the particles in 5 s is

A particle is moving along the x-axis with an acceleration a = 2x where a is in ms^(–2) and x is in metre. If the particle starts from rest at x=1 m, find its velocity when it reaches the position x = 3.

A particle is moving along the x-axis with an acceleration a = 2x where a is in ms^(–2) and x is in metre. If the particle starts from rest at x=1 m, find its velocity when it reaches the position x = 3.

A particle is moving along x-axis with acceleration a=a_(0)(1-t//T) where a_(0) and T are constants. The particle at t=0 has zero velocity. Calculate the distance(position ) of particle.

A particle confined to motion along an x axis moves with constant acceleration from x=2.0m to x=8.0 m during a 2.5 s time interval. The velocity of the particle at x=8.0m is 2.8 m/s. What is the constant acceleration during this time interval ?

A particle is moving along x-direction with a constant acceleration a. The particle starts from x=x_0 position with initial velocity u. We can define the position of the particle with time by the relation x=x_0+ut+(1)/(2)at^2 plot the position of the particle in relation with time is following situations (i) If initial position of the particle is on negativ x-axis, initial velocity is positive and acceleration is negative. (ii) If initial position is positive, initial velocity is negative and acceleration is positive.

A particle is moving along x-direction with a constant acceleration a. The particle starts from x=x_0 position with initial velocity u. We can define the position of the particle with time by the relation x=x_0+ut+(1)/(2)at^2 plot the position of the particle in relation with time is following situations (i) If initial position of the particle is on negativ x-axis, initial velocity is positive and acceleration is negative. (ii) If initial position is positive, initial velocity is negative and acceleration is positive.

A particle is moving with initial velocity 1m/s and acceleration a=(4t+3)m/s^(2) . Find velocity of particle at t=2sec .