`tan^(2)theta-tan^(2)(90^(@)-theta)=(sin^(2)theta-cos^(2)theta)/(sin^(2)theta cos^(2)theta)`

If tan theta=(3)/(4), then (4sin^(2)theta-2cos^(2)theta)/(4sin^(2)theta+3cos^(2)theta)

If tan theta=(3)/(4), then (4sin^(2)theta-2cos^(2)theta)/(4sin^(2)theta+3cos^(2)theta)

(sec^(2)theta-sin^(2)theta)/(tan^(2)theta)=cosec^(2)theta-cos^(2)theta

Prove that :(sin theta cos(90^(0)-theta)cos theta)/(sin(90^(0)-theta))+(cos theta sin(90^(0)-theta)sin theta)/(cos(90^(@)-theta))=1csc^(2)(90^(@)-theta)-tan^(2)theta=cos^(2)(90^(@)-theta)+cos^(2)theta

(1+sin2 theta-cos2 theta)/(1+sin2 theta+cos2 theta)=tan theta

If sin theta = 12/13 (0^(@) lt theta lt 90^(@)) , find the value of (sin^(2) theta - cos^(2)theta)/(2 sin theta cos theta) xx (1)/(tan^(2)theta) .

(sin theta-2sin^(3)theta)/(2cos^(3)theta-cos theta)=tan theta

(sin theta" cosec "theta tan theta cot theta)/(sin^(2)theta+cos^(2)theta)

Prove that (cos^(2) theta)/(1-tan theta)+(sin^(3) theta)/(sin theta - cos theta) =1 + sin theta cos theta .