" (2) Pape that "3+2sqrt(5)" is inpotional "

Evaluate : ( sqrt(2) - sqrt(3) + sqrt(5) )times ( sqrt(2) + sqrt(3) + sqrt(5) )

The simplest rationalising factor of 2sqrt(5)-sqrt(3) is (a) 2sqrt(5)+\ 3 (b) 2sqrt(5)+sqrt(3) (c) sqrt(5)+sqrt(3)\ \ (d) sqrt(5)-sqrt(3)

(2sqrt3 + sqrt5)(2sqrt3 - sqrt5)

The simplest rationalising factor of 2sqrt(5)-sqrt(3) is 2sqrt(5)+3( b) 2sqrt(5)+sqrt(3)(c)sqrt(5)+sqrt(3) (d) sqrt(5)-sqrt(3)

(sqrt(5)+sqrt(3))((3sqrt(3))/(sqrt(5)+sqrt(2))-sqrt(5)/(sqrt(3)+sqrt(2))) is equal to :

If x=(sqrt(5)+sqrt(3))/(sqrt(5)-sqrt(3)) and y=(sqrt(5)-sqrt(3))/(sqrt(5)+sqrt(3)), then (x+y) equals (a) 2(sqrt(5)+sqrt(3))( b) 2sqrt(15)(c)8 (d) 16

Simplify: (i) (5+\ sqrt(5))\ (5-\ sqrt(5)) (ii) (3+2sqrt(2))\ (3-2sqrt(2))

Simplify (i) (4+ sqrt(5))/(4-sqrt(5))+(4-sqrt(5))/(4+sqrt(5)) (ii) (1)/(sqrt(3) + sqrt(2)) - (2)/(sqrt(5)-sqrt(3)) -(2)/(sqrt(2) - sqrt(5)) (iii) (2+sqrt(3))/(2-sqrt(3)) + (2-sqrt(3))/(2+sqrt(3)) + (sqrt(3)-1)/(sqrt(3)+1) (iv) (2+sqrt(6))/(sqrt(2)+sqrt(3))+(6sqrt(2))/(sqrt(6)+sqrt(3)) -(8sqrt(3))/(sqrt(6)+sqrt(2))