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["The arithmetic mean of the following frequency ",multicolumn3c" distribution is 25."],["Determine the value of p.",multicolumn5|c|" [CBSE 2006] "],[hline" Class",0-10,10-20,20-30,30-40,40-50],[hline" Frequency",5,18,15,p,6],[hline]

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For the following frequency distribution draw a cumulative frequency curve of "'more than type'" and hence obtain the median value [["Class",0-10,10-20,20-30,30-40,40-50,50-60,60-70],["Frequency",5,15,20,23,17,11,9]]

The median from the following distribution is {:("Class" :,5-10,10-15,15-20,20-25,25-30,30-35,35-40,40-45),("Frequency":,5,6,15,10,5,4,2,2):}

The median from the following distribution is {:("Class" :,5-10,10-15,15-20,20-25,25-30,30-35,35-40,40-45),("Frequency":,5,6,15,10,5,4,2,2):}

Calculate mode from the following data : {:("Class Interval",0-10,10-20,20-30,30-40,40-50),("Frequency"," "2," "5," "7," "5," "2):}

If the mode for the following frequency distribution is 22 and 10 gt y gt x, "them "y= {:("Class-interval:", 0-10,10-20,20-30,30-40,40-50,"Total"),("Frequency:", 5,8,10,x,y,30):}

If the mode for the following frequency distribution is 22 and 10 gt y gt x, "them "y= {:("Class-interval:", 0-10,10-20,20-30,30-40,40-50,"Total"),("Frequency:", 5,8,10,x,y,30):}

The median class in the following frequency distribution is {:("Class interval :",0-10,10-20,20-30,30-40,40-50),("Frequency :",12,13,25,20,10):}

The median class in the following frequency distribution is {:("Class interval :",0-10,10-20,20-30,30-40,40-50),("Frequency :",12,13,25,20,10):}

If the mean of the following distribution is 27, find the value of p . Class: 0-10 10-20 20-30 30-40 40-50 Frequency: 8 p 12 13 10

If the mean of the following distribution is 27, find the value of p . Class: 0-10 10-20 20-30 30-40 40-50 Frequency: 8 p 12 13 10