Let `A=[[0,sin alpha,sin alpha sin beta],[-sin alpha,0,cos alpha cos beta],[-sin alpha sin beta,-cos alpha cos beta,0]]` then

If cos alpha+cos beta=0=sin alpha+sin beta then cos2 alpha+cos2 beta=

det[[cos alpha cos beta,cos alpha sin beta,-sin alpha-sin beta,cos beta,0sin alpha cos beta,sin alpha sin beta,cos alpha]]

Evaluate Delta=|[0, sin alpha, -cos alpha],[ -sin alpha, 0 , sin beta],[ cos alpha, -sin beta, 0]|

Evaluate ,,,|cos alpha cos beta,cos alpha sin beta,-sin alpha-sin beta,cos beta,0sin alpha,cos beta,sin alpha sin beta,cos alpha]|

If cos alpha+cos beta=0=sin alpha+sin beta, then cos2 alpha+cos2 beta is equal to

Evaluate |[cos alpha cos beta, cos alpha sin beta, -sin alpha],[ -sin beta, cos beta, 0],[ sin alpha cos beta, sin alpha sin beta, cos alpha]|

(cos alpha + cos beta)/( sin alpha - sin beta) + (sin alpha + sin beta)/( cos alpha - cos beta ) =

Evaluate: quad =|0sin alpha-cos alpha-sin alpha0sin beta cos alpha-sin beta0

sin alpha sin beta-cos alpha cos beta=1 then show that tan alpha+tan beta=0