[" Consider "f(x)=tan^(-1)(sqrt((1+sin x)/(1-sin x))),x in(0,(pi)/(2))." A normal to "y=f(x)" at "x=(pi)/(6)" also passes through "],[" the point: "]

Consider f(x)=tan^(-1)(sqrt((1+sinx)/(1-sinx))), x in (0,pi/2)dot A normal to y=f(x) at x=pi/6 also passes through the point:

Consider f(x) = tan^-1(sqrt((1+sinx)/((1-sinx)))), x in (0,pi/2) A normal to y = f(x) at x = pi/6 also passes through the point

Consider f(x)=tan^-1(sqrt((1+sinx)/(1-sinx)),x in(0,pi/2) . A normal to y=f(x) at x=pi/6 also passes through the point :

Consider f(x)=tan^(-1)(sqrt((1+sinx)/(1-sinx))), x in (0,pi/2)dot A normal to y=f(x) at x=pi/6 also passes through the point: (1) (0, 0) (2) (0,(2pi)/3) (3) (pi/6,0) (4) (pi/4,0)

Consider f(x)=tan^(-1)(sqrt((1+sinx)/(1-sinx))), x in (0,pi/2)dot A normal to y=f(x) at x=pi/6 also passes through the point: (1) (0, 0) (2) (0,(2pi)/3) (3) (pi/6,0) (4) (pi/4,0)

Consider f(x)=tan^(-1)(sqrt((1+sinx)/(1-sinx))), x in (0,pi/2)dot A normal to y=f(x) at x=pi/6 also passes through the point: (1) (0, 0) (2) (0,(2pi)/3) (3) (pi/6,0) (4) (pi/4,0)

If y=tan^(-1)sqrt((1-sin x)/(1+sin x)), then the value of (dy)/(dx) at x=(pi)/(6) is.

If f (x) = tan ^(-1)sqrt((1 + sin x )/(1 - sin x)), 0 le x le (pi)/(2) then f' ((pi)/(6)) =?

If f (x) = tan ^(-1)sqrt((1 + sin x )/(1 - sin x)), 0 le x le (pi)/(2) then f' ((pi)/(6)) =?