(1)/(v)+(1)/(u)=(1)/(f)

The focal length of a mirror is given by (1)/(v)-(1)/(u)=(2)/(f) . If equal errors alpha are made in measuring u and v then relative error in f is

The focal length of a mirror is given by (1)/(v)-(1)/(u)=(2)/(f). If equal errors alpha are made inmeasuring u and v. Then relative error in f is

What is f in mirror formula (1)/(u)+(1)/(v)=(1)/(f) ?

If (1)/(f)=(1)/(u)+(1)/(v) , then make v as the subject of the formula.

If (1)/(f)=(1)/(u)+(1)/(v) , then make v as the subject o the foormula. Also find v, if u=12 units and f=3 units

The focal length of a less is given by the formula (1)/(f)=(1)/(u)+(1)/(v) . Make f as the subject of the formula. if u=20cm and v=30, then find f. The following steps are involved in solving the above problem. Arrange them in sequential order. (A) Given (1)/(f)=(1)/(u)+(1)/(v) (B) rArr f=(uv)/(u+v) (C) f=(20xx30)/(20+30)=(600)/(50)=12 cm. (D) rArr (1)/(f)=(v+u)/(uv)

The focal length of a mirror is give by (1)/(f)=(1)/(u)+(1)/(v) , where 'u' represents object distance, 'v' image distance and 'f' local length. The maximum relative error is

The focal length of a mirror is give by (1)/(f)=(1)/(u)+(1)/(v) , where 'u' represents object distance, 'v' image distance and 'f' local length. The maximum relative error is