10y+40+3x-x^(2)

The equation to the locus of a point P for which the distance from P to (0,5) is double the distance from P to y -axis is 1) 3x^(2)+y^(2)+10y-25=0 2) 3x^(2)-y^(2)+10y+25=0 3) 3x^(2)-y^(2)+10y-25=0 4) 3x^(2)+y^(2)-10y-25=0

The equation of the circle whose diameter is the common chord of the circles; x^(2)+y^(2)+3x+2y+1=0&x^(2)+y^(2)+3x+4y+2=0 is x^(2)+y^(2)+8x+10y+2=0x^(2)+y^(2)-5x+10y+7=0x^(2)+y^(2)-5x+4y+7=02x^(2)+2y^(2)+6x+2y+1=0 None of these

Factorise by taking out the common factors : xy(3x^(2) - 2y^(2)) - yz(2y^(2) - 3x^(2)) + zx(15x^(2) - 10y^(2))

The perimeter of a triangle is 20 and the points (-2, -3) and (-2,3) are two of the vertices of it. Then the locus of third vertex is : (x-2), y = 49 40 (x+2) y? = 1 49 40 (x+2)? y? 1 40 49 (x-2) y = 40 49

The area of the region between y=3x^(3)-x^(2)-10x and y= -x^(2)+2x is

If the equation (10x-5)^(2)+(10y -4)^(2)=lambda^(2) (3x+4y-1)^(2) represents a hyperbola then

(b) Factorize 4x^(3) - 10y^(3) - 8x^(2) y + 5xy^(2)

I. x^(2)/2 + x - 1/2 = 1 II. 3y^(2) - 10y + 8 = y^(2) + 2y - 10