given the function `={x^2;0lt=xlt=1sqrt(x):1lt=xlt=2` then evaluate `int_0^2f(x)dx=`

A curve is given by y={(sqrt(4-x^2)),0lt=x<1and sqrt((3x)),1lt=xlt=3. Find the area lying between the curve and x-axis.

A curve is given by y={(sqrt(4-x^2)),0lt=x<1and sqrt((3x)),1lt=xlt=3. Find the area lying between the curve and x-axis.

A curve is given by b yy={(sqrt(4-x^2)),0lt=x<1sqrt((3x)),1lt=xlt=3. Find the area lying between the curve and x-axis.

A curve is given by b yy={(sqrt(4-x^2)),0lt=x<1sqrt((3x)),1lt=xlt=3. Find the area lying between the curve and x-axis.

Differentiate w.r.t. x the function sin^(-1)(xsqrt(x)),0lt=xlt=1

If the area of the region {(x , y):0lt=ylt=x^2+1,0lt=ylt=x+1,0lt=xlt=2} is A , then the value of 3A-17 is____

If the area of the region {(x , y):0lt=ylt=x^2+1,0lt=ylt=x+1,0lt=xlt=2} is A , then the value of 3A-17 is____

If the area of the region {(x , y):0lt=ylt=x^2+1,0lt=ylt=x+1,0lt=xlt=2} is A , then the value of 3A-17 is____

The relation f is defined by f(x)={x^2,0lt=xlt=3 3x ,3lt=xlt=10 The relation g is defined by g(x)={x^2,0lt=xlt=3 3x ,2lt=xlt=10 Show that f is a function and g is not a function.

The relation f is defined by f(x)={x^2,0lt=xlt=3 3x ,3lt=xlt=10 The relating g is defined by g(x)={x^2,0lt=xlt=3 3x ,2lt=xlt=10 Show that f is a function and g is not a function.