((x)/(2)+(y)/(3))^(3)-((x)/(2)-(y)/(3))^(3)

Factorize: ((x)/(2)+y+(z)/(3))^(3)+((x)/(3)-(2y)/(3)+z)^(3)+(-(5x)/(6)-(y)/(3)-(4z)/(3))^(3)

Factorise : ((x)/(2)+y+(z)/(3))^(3)+((x)/(3)-(2y)/(3)+z)^(3)-((5x)/(6)+(y)/(3)+(4z)/(3))^(3)

Factorize: (x/2+y+z/3)^3+\ \ (x/3-(2y)/3+z)^3+(-(5x)/6-y/3-(4z)/3)^3

((x +y)^(3) + (x-y)^(3))/(2) -y (3x^(2) + y^(2)) = ______

Simplify: ((x^(2)-y^(2))^(3) + (y^(2) - z^(2))^(3) + (z^(2) -x^(2))^(3))/((x-y)^(3) + (y-z)^(3) + (z-x)^(3))

Find ((x^(2)-y^(2))^(3) + (y^(2) -z^(2))^(3)+ (z^(2) -x^(2))^(3))/((x-y)^(3) + (y-z)^(3) + (z-x)^(3))

The following are the steps involved in factorizing 64 x^(6) -y^(6) . Arrange them in sequential order (A) {(2x)^(3) + y^(3)} {(2x)^(3) - y^(3)} (B) (8x^(3))^(2) - (y^(3))^(2) (C) (8x^(3) + y^(3)) (8x^(3) -y^(3)) (D) (2x + y) (4x^(2) -2xy + y^(2)) (2x - y) (4x^(2) + 2xy + y^(2))