" iv) "x^(3)-7x^(2)+36=0," given one root being twice the other."

solve x^3-7x^2+36=0 given one root being twice the other .

solve x^3-7x^2+36=0 given one root being twice the other .

Solve x^3 -7x^2 + 36 =0 given one root being twice the other .

Find the value of q so that the equations 2x^(2) - 3qx + 5q =0 has one root which is twice the other.

In the equation x^(2)+kx+54=0 , one root is twice the other root. The value(s) of k is (are)

Determine k and solve the equation 2x^3-6x^2+3x+k=0 if one of its roots is twice the sum of the other two roots.

Determine k and solve the equation 2x^3 - 6x^2 + 3x+k = 0 if one of its roots is twice the sum of the other two roots.

The roots of 3x^(3) - 4x^(2) +x +88 = 0, one root being 2 + sqrt(7) i are