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Let veca vecb and vecc be pairwise mutua...

Let `veca vecb and vecc` be pairwise mutually perpendicular vectors, such that `|veca|=1, |vecb|=2, |vecc| = 2`, the find the length of ` veca +vecb + vecc`.

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`|veca+vecb+vecc|^(2)=(veca+vecb+vecc).(veca+vecb+vecc)`
`= |veca|^(2)+|vecb|^(2)+|vecc|^(2)+2veca.vecb + 2veca.vecb+2vecb.vecc+2vecc.veca`
`=1+4+4+0+0+0=9`
`Rightarrow |veca+vecb+vecc|=3`
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