Find the equation of the tangent to the curve `y=-5x^2+6x+7` at the point `(1//2,\ 35//4)` .

Find the equations of the tangent line to the curve: y=x^3 - 3x +5 at the point (2,7)

Find the equation of the tangent line to the curve : y=x^(3)-3x+5 at the point (2, 7)

Find the equations of the tangent line to the curve: y = 2x^2 + 3y^2 = 5 at the point (1,1)

Find the equation of the tangent to the curve y=x^4-6x^3+13x^2-10x+2 at the point x=1 and y=0.

Find the equation of tangent to the curve ? y=x^(2) + 4x at the point whose ordinate is 5

Find the equation of the tangent and the normal to the curve y = x^(2) + 4x + 1 at the point where x = 3

Find the equation of the tangent to the curve y = (x-7)/((x-2)(x-3)) at the point where it cuts the x-axis.

Find the equation of the tangent to the curve y=(x-7)/((x-2)(x-3)) at the point where it cuts the x-axis.

Find the equation of the tangent to the curve y=(x-7)/((x-2)-(x-3)) at the point where it cuts the x-axis.