On measuring diameter of a wire with help of screw gauge, main scale reading is `1mm` and `6th` division of circular scale lying very reference line. On measuring zero error, it is found that zero of circular scale has advanced from references line by `3` divisions on circular scale, then corrected diameter is

While measuring diameter of a wire using a screw gauge the main scale reading is 7mm and zero of circular scale is 35 divisions above the reference line. If the screw gauge has a zero error of -0.003cm , the correct diameter of the wire is (given least count =0.001cm )

Main scale of a screw gauge is 3mm and 42 division of circular scale of 100 divisions coincides with reference line then find the diameter of the cylinder

The pitch of a screw gauge is 1 mm and there are 100 divisions on the circular scale. In measuring the diameter of a sphere there are six divisions on the linear scale and forty divisions on circular scale coincide with the reference line. Find the diameter of the sphere.

The pitch of a screw gauge is 1 mm and there are 100 divisions on the circular scale. In measuring the diameter of a sphere there are six divisions on the linear scale and forty divisions on circular scale coincide with the reference line. Find the diameter of the sphere.

Distance travelled by linear scale of screw gauge during two full rotation of circular scale is 1mm and circular scale has 50 divisions. In an experiment to measure thickness of a plate, six divisions of main scale are clearly visible and 28^(th) division of circular scale coincides with reference line. Moreover when studs touch each other, zero of circular scale lies 4 division below the reference line, thickness of the plate will be:

If in a screw gauge, zero mark of the circular scale remains on right of reference line and does not cross it and 2nd division on circular scale comes on references line. Then zero correction is