Re((z-8i)/(z+6))=0," the locus of "z" is equal to: "

Let I Arg((z-8i)/(z+6))=pmpi/2 II: Re ((z-8i)/(z+6))=0 Show that locus of z in I or II lies on x^2+y^2+6^x – 8^y=0 Hence show that locus of z can also be represented by (z-8i)/(z+6)+(bar(z)-8i)/(barz+6)=0 Further if locus of z is expressed as |z + 3 – 4i| = R, then find R.

If Im((z-i)/(2i))=0 then the locus of z is

If |(z-i)/(z+i)|=1 then the locus of z is

If |(z-i)/(z+i)|=1 , then the locus of z is

if |z-1|=|z-i| then locus of z is

If Re ((z+3)/(z-2i))=0 then the locus of z = x +iy is

If "Re"((z-8i)/(z+6))=0 , then lies on the curve

If Re (z^2)=2 then the locus of z is

If "Re"((z-8i)/(z+6))=0 , then z lies on the curve