`f(x)={(x^3+x^2-16 x+20)/((x-2)^2), x!=2k ,k , x=2` . Find the value of k, so that the following function is continuous at x=2.

Similar Questions

Explore conceptually related problems

For what value of k is the following function continuous at x=2? f(x)={2x+1; x 2}

For what value of k is the following function continuous at x=2? f(x)={[2x+1,;,x 2]}

The value of k, so that the function f(x)={:{(kx)-5k, xle2),(3,xgt2):} is continuous at x = 2, is:

If f(x)={(x^3+x^2-16x+20)/(x-2)^2,x ne 0 k, x=0 is continuous for all real values of x, find the value of K.

Find the value of k for which the function f(x)={k x+5, if x lt=2x-1, if x >2} is continuous at x=2

If f(x)=( x^3+x^2-16x + 20)/(x-2)^2 if x!=2 = k if x = 2 is continuous at for all x, then what is the value of k.

Consider f(x)={(3x-8,xle5),(2k,x>5):} . Find the value of k if f(x) is continuous at x=5 .

If f(x) = {:{((x^3+x^2-16x+20)/((x-2)^2), x ne2), (k, x =2):} is continuous at x =2, find the value of 'k'.

Find the value of k, such that the function f(x) = {(k(x^2-2x), if x = 0):} at x=0 is continuous.