Function `f(x)` is defined as `f(x)={(x-1)/(2x^2-7x+5), x!=1 and -1/3, x=1` . Is `f(x)` differentiable at `x = 1` if yes find `f'(1)?`

If f(x)=(x-1)/(2x^(2)-7x+5) for x!=1 and f(x)=-(1)/(3) for x=1 then f'(1)=

A function f(x) is defined as f(x)=x^2+3 . Find f(0), F(1), f(x^2), f(x+1) and f(f(1)) .

A function f(x) is defined as f(x)=x^2+3 . Find f(0), F(1), f(x^2), f(x+1) and f(f(1)) .

The function f defined by f(x)=[2x^(2)+3f or x<=1 and 3x+2f or x<1 is neither differentiable nor continuousat x=1

If a function f(x) is defined as f(x) = {{:(-x",",x lt 0),(x^(2)",",0 le x le 1),(x^(2)-x + 1",",x gt 1):} then a. f(x) is differentiable at x = 0 and x = 1 b. f(x) is differentiable at x = 0 but not at x = 1 c. f(x) is not differentiable at x = 1 but not at x = 0 d. f(x) is not differentiable at x = 0 and x = 1

If the function f be defined by f(x) =(2x +1)/(1-3x) , then f ^(-1) (x) is-

Find the values of a and b , if the function f(x) defined by f(x)={x^2+3x+a ,\ \ xlt=1b x+2,\ \ \ \ \ \ \ \ \ \ x >1 is differentiable at x=1 .