Equation of trajectory| Projectile questions| Non ground-to-ground projectile

Projectile Motion|Questions

The equation of trajectory of a projectile thrown from a point on the ground is y=(x-x^(2)/40) m. If g=10ms^(-2) The maximum height reached is

Equation of trajector of ground to ground projectile is y=2x-9x^(2) . Then the angle of projection with horizontal and speed of projection is : (g=10m//s^(2))

At the top of the trajectory of projectile the

The question given below consist of an assertion and the reason . Use the following key to choose appropriate answer: Assertion : There is a case of ground -to - ground projectile . When projectile is fired at an its path where instantaneous velocity becomes perpendicular to its initial velocity . Reason : In case of ground -to- ground projectile projected at an angle theta , maximum possible deviation is 2 theta ,

Projectile Motion|Range|Questions

Average velocity in projectile|| Equation OF trajectory|| Collision on wall in projectile

Trajectory Of Horizontal Projectile

Questions|Projectile From A Height|Questions