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[" 1."sin A+sin3A+sin5A+sin7A=],[" 1) "4...

[" 1."sin A+sin3A+sin5A+sin7A=],[" 1) "4sin A cos2A cos4A],[" 2) "4sin A cos2A cos3A],[" 3) "4cos A sin2A sin4A],[" 4) "4cos A cos2A sin4A]

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( sin 4 A sin 3A - sin 5A sin 2A+ sin 7A sin 4A )/(cos 2A cos 3A - cos 2A * cos 7A + cos A * cos 10A )=

sin4A = 4sin A cos ^ (3) A-4cos A sin ^ (3) A

(sin A sin2A + sin3A sin6A + sin4A sin13A) / (sin A cos2A + sin3A cos6A + sin4A cos13A) = tan9A

(sin A+sin3A+sin5A+sin7A)/(cos A+cos3A+cos5A+cos7A)=tan4A

sin4A = 4sin A * cos ^ (3) A-4cos A * sin ^ (3) A

sin3A+sin2A-sin A=4sin A*cos((A)/(2))*cos((3A)/(2))

Prove that: (sin2A sin3A-sin4A sin5A+sin3A sin6A)/(cos2A cos3A-cos4A cos5A+cos3A cos6A)=tan A tan4A

Prove that: \ sin3A+sin2A-sin A=4sin A cos (A/2)cos((3A)/2)

( sin A + sin 3A + sin 5A + sin 7A)/(cos A + cos 3 A + cos 5 A + cos 7A) = tan 4A.

(cos3A-cos A)/(sin3A-sin A)+(cos2A-cos4A)/(sin4A-sin2A)=(sin A)/(cos2A cos3A)