Benzene and Toluene form ideal solution over the entire range of composition. The vapour pressure of pure benzene and toluene at 300 K are 50.71 mm of Hg and 32.06 mm of Hg respectively. Calculate the mole fraction of benzene in vapour phase if 80g of benzene is mixed with 100g of toluene.

Benzene and toluene form an ideal solution over the entire range of composition. The vapour pressure of pure benzene and toluene at T(K) are 50mm Hg and 40 mm Hg respectively. What is the mole fraction of toluene in vapour phase when 117 g of benzene is mixed with 46g of toluene? (molar mass of benzene and toluene are 78 and 92 g mol^(-1) respectively).

The vapour presssures of pure benzene and toluene are 160 and 60 mm Hg respectively. The mole fraction of benzene in vapour phase in contact with equimolar solution of benzene and toluene is

A solute has 2:3 molar ratio of toulene to benzene. The vapour pressure of benzene and toulene at 25^@C are 95 and 28 bar respectively. The mole fraction of Toulene vapour is

A solution has 1:4 molar ratio of pentane and hexane. The vapour pressure of pure hydrocarbons at 20^@C are 440 mm Hg for pentane and 120 mm of Hg for hexane. The mole fraction of pentane in vapour phase would be

A solution has 1:4 molar ratio of pentane and hexane. The vapour pressure of pure hydro-carbons at 20^@C are 440 mm Hg for pentane and 120 mm of Hg for hexane. The mole fraction of pentane in vapour phase would be

Vapour pressures of para xylene and methylbenezene at 90^@C are respectivley 150 mm and 400 mm. Calculate the mole fraction of dimethyl benzene in the mixture that boils at 90^@C , when the pressure is 0.5 atm.

At 300 K an ideal solution is formed by mixing 460 g of toluene with 390 k benzene. If the vapour pressure of pure toluene and respectively the mole fraction of toluene in vapour phase is