Voltage applied to an `AC` circuit and current flowing in it is given by
`V=200sqrt2sin(omegat+pi/4)` and `i=-sqrt2cos(omegat+pi/4)`
Then, power consumed in the circuited will be

For an AC circuit V=15sin omegat and I=20cos omegat the average power consumed in this circuit is

When a voltage V_(s)=200 sqrt(2) sin (100 t) V is applied to an ac circuit the current in the circuit is found to be i=2 sin [omega t + (pi//4)]A . Find the average power consumed in the circuit.

When a voltage V_(s)=200 sqrt(2) sin (100 t) V is applied to an ac circuit the current in the circuit is found to be i=2 sin [omega t + (pi//4)]A . Find the average power consumed in the circuit.

When a voltage V_(s)=200 sqrt(2) sin (100 t) V is applied to an ac circuit the current in the circuit is found to be i=2 sin [omega t + (pi//4)]A . Find the average power consumed in the circuit.

When a voltage v_(s)=200sqrt2 sin (omega t=15^(@)) is applied to an AC circuit the current in the circuit is found to be i=2som (omegat+pi//4) then average power consumed in the circuit is

For an AC circuit the potential difference and current are given by V = 10 sqrt(2) sin omegat (in V) and i = 2 sqrt(2) cos omegat (in A) respectively. The power dissipated in the instrument is

For an AC circuit the potential difference and current are given by V = 10 sqrt(2) sin omegat (in V) and i = 2 sqrt(2) cos omegat (in A) respectively. The power dissipated in the instrument is

When a voltage v_(S)=200sqrt2 sin (omega t+15^(@)) is applied to an AC circuit the current in the circuit is found to be i=2 sin (omegat+pi//4) then average power concumed in the circuit is (A) 200 watt , (B) 400sqrt2 watt , (C ) 100sqrt6 watt , (D) 200sqrt2 watt

When a voltage v_(S)=200sqrt2 sin (omega t+15^(@)) is applied to an AC circuit the current in the circuit is found to be i=2 sin (omegat+pi//4) then average power concumed in the circuit is (A) 200 watt , (B) 400sqrt2 watt , (C ) 100sqrt6 watt , (D) 200sqrt2 watt