Ten speakers including `A ,B ,C` speak at a function.Given that `A` speaks before `B,B` speaks before `C,` the chance that `A,B,C` are adjacent speakers is

Three persons A,B and C speak at a function along with 5 other persons.If the persons speak at random,find the probability that A speaks before B and B speaks before C

Three persons A,B and C are to speak at a function with 5 other persons.If the persons speakin random order,the probability that A speaks before B and C speaks before A in that order is

Among 10 persons,A,B,C are to speak at a function.The number of ways in which it can be done if A wants to speak before B and B wants to speak before C is a.10!/24b.9!/6c10!/6d d.none of these

There are 5 speakers A,B,C,D and E. The number of ways in which A will speak always before B is:

A, B, C are three persons among 7 persons who speak at a function. The number of waysin which it can be done if 'A' speaks before 'B' and 'B' speaks before 'C' is