A 0.05 M NaOH solution offered a resistance of 31.6 `Omega` in a conductivity cell at 298 K. If the cell constant of the conductivity cell is 0.367 `cm^(-1)`, find out the specific and molar conductance of the sodium hydroxide solution.

0.05M NaOH solution offered a resistance of 31.69 Omega in a conductivity cell at 298K. If the cell constant of the conductivity cell is 0.367cm^(-1) the molar conductivity of the NaOH solution is

Define' specific and equivalent conductance'. How are they related ? 0.05 M NaOH solution offered a resistance of 31.6 ohm in a conductivity cell at 298 K . If the cell constant of the cell is 0.376cm^-1 , calculate the molar conductance of the NaOH solution.

A 0.05 M NaOH solution offered a resistance of 31.6 ohms in a conductivity cell. If the cell constant of the conductivity cell is 0.378 cm^(-1) , determine the molar conductivity of sodium hydroxide solution at this temperature.

0.05 M NaOH solution offered a resistance of 3.1*6Omega in a conductivity cell at 298 K. If the cell constant of the cell si 0*367cm^(-1), calculate the molar conductivity of NaOH solution.

0.05 "M" NaOH solution offered a resistance of 31.6 ohm in a conductivity cell at 298 K. If the cell constant of the cell is 0.367 cm^(_1) calculate the molar conductivity of the NaOH solution.

0.05 M NaOH solution offers a resistance of 32 ohms in a conductivity cell at 298K. If the cell constant of the cell is 0.376 cm^(-1) , Calculate the molar conductance of NaOH solution.