1g mixture of equal number of mole of `Li_(2)CO_(3)` and other metal carbonate `(M_(2)CO_(3))` required 21.6mL of 0.5 N HCl for complete neutralisation reaction. What is the apoproximate atomic mass of the other metal?

1g mixture of equal number of mole of Li_2 Co_3 and other metal carbonate (M_2 CO_3) required 21.6 mL of 0.5 NHCI for complete neutralisation reaction. What is the approximate atomic mass of the other metal ?

1g mixture of equal number of mole of Li_2 Co_3 and other metal carbonate (M_2 CO_3) required 21.6 mL of 0.5 NHCI for complete neutralisation reaction. What is the approximate atomic mass of the other metal ?

1 gm metal carbonate requires 200 ml of 0.1N HCl for complete neutralization. What is the equivalent weight of metal carbonate:-

1 gm metal carbonate requires 200 ml of 0.1N HCl for complete neutralization. What is the equivalent weight of metal carbonate:-

1 gm metal carbonate requires 200 ml of 0.1N HCl for complete neutralization. What is the equivalent weight of metal carbonate:-

0.50 g of a mixture of K_(2)CO_(3) and Li_(2)CO_(3) required 30 mL of 0.25 N HCl solution for neutralization. What is % composition of mixure?

1.00 g of a mixture, consisting of equal number of moles of carbonates of two alkali metals, required 44.4 " mL of " 0.5 N-HCl for complete reaction. If the atomic weight of one of the metal is 7.00. Find the atomic weight of the other metal.

1.00 g of a mixture, consisting of equal number of moles of carbonates of two alkali metals, required 44.4 " mL of " 0.5 N-HCl for complete reaction. If the atomic weight of one of the metal is 7.00. Find the atomic weight of the other metal. What will be the total amount of sulphate formed on quantitative conversion of 1.00 g of the mixture into sulphates?