MA. B. C. D are the angles of a cyclic quadrilateral then cos 'fr cos B + cos C-cos D =

If A,B,C,D are the angles of a cyclic quadrilateral then cos A + cos B+ cos C + cos D=

I: If A,B,C,D are angles of a cyclic quadrilateral then cos A + cos B + cos C + cos D=0 II : If A,B,C,D are the angles of a quadrilateral then cos""(A+B)/(2) + cos""(C+D)/(2) =0

If A,B,C,D are the angles of a cyclic quadrilateral and cos A+cos B= K(cos C + cos D), then the value of K is

If A ,B ,C ,D are angles of a cyclic quadrilateral, then prove that cos A+cos B+cos C+cos D=0

If A ,B ,C ,D are angles of a cyclic quadrilateral, then prove that cos A+cos B+cos C+cos D=0

If A ,B ,C ,D are angles of a cyclic quadrilateral, then prove that cos A+cos B+cos C+cos D=0

If A,B,C,D are angles of a cyclic quadrilateral,prove that cos A+cos B+cos C+cos D=0

If A ,\ B ,\ C ,\ D are angles of a cyclic quadrilateral, prove that cos A+cos B+cos C+cos D=0.

If A,B,C,D are angles of a cyclic quadrilateral,then prove that cos A+cos B+cos C+cos D=0