If asin^(-1)x-bcos^(-1)x=c , then asin^...

If `asin^(-1)x-bcos^(-1)x=c ,` then `asin^(-1)x+bcos^(-1)x` is equal to (a)`0 `(b) `(pia b+c(b-a))/(a+b)` (c)`pi/2` (d) `(pia b+c(a-b))/(a+b)`

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