A particle is projected with a speed v and an angle `theta` to the horizontal. After a time t, the magnitude of the instantaneous velocity is equal to the magnitude of the average velocity from 0 to t. Find t.

A particle projected with velocity u at angle theta with horizontal at t=0. What is the magnitude of change in the velocity of the particle when it is at maximum height?

A projectill is projected at an angle (alpha gt 45^(@)) with an initial velocity u. The time t, at which its magnitude of horizontal velocity will equal the magnitude of vertical velocity is :-

A projectill is projected at an angle (alpha gt 45^(@)) with an initial velocity u. The time t, at which its magnitude of horizontal velocity will equal the magnitude of vertical velocity is :-

A projectill is projected at an angle (alpha gt 45^(@)) with an initial velocity u. The time t, at which its magnitude of horizontal velocity will equal the magnitude of vertical velocity is :-

A particle of mass m is projected with a speed u at an angle theta with the horizontal. Find angular momentum of particle after time t about point of projection.

A particle is projected with speed u at angle theta with horizontal from ground . If it is at same height from ground at time t_(1) and t_(2) , then its average velocity in time interval t_(1) to t_(2) is

A particle is projected with speed u at angle theta with horizontal from ground . If it is at same height from ground at time t_(1) and t_(2) , then its average velocity in time interval t_(1) to t_(2) is

A particle is projected with velocity v at an angle theta aith horizontal. The average angle velocity of the particle from the point of projection to impact equals

A particle is projected with velocity v at an angle theta aith horizontal. The average angle velocity of the particle from the point of projection to impact equals

A particle is projected with speed 100m/s at angle theta=60^(@) with the horizontal at time t=0" . At time 't' the velocity vector of the particle becomes perpendicular to the direction of velocity of projection.Its tangential acceleration at time 't' is (g =10m/s^(2))