The shortest distance from the point (1,2,-1) to the surface of the sphere x^(2)+y^(2)+z^(2)=54 is a) 3sqrt(6) b) 2sqrt(6) c) sqrt(6) d)2
If the angle betweenthe lines whose direction cosines are (-(2)/(sqrt(21)), (C )/(sqrt(21)), (1)/(sqrt(21))) and ((3)/(sqrt(54)), (3)/(sqrt(54)), -(6)/(sqrt(54))) is (pi)/(2) , then the value of C is
Divide and write the answer in simplest form : sqrt(54)÷ sqrt(27)
Area of a regular polygon of n sides is given by A= n(sqrt(3))/(4)a^(2)sq . Units . Make 'a' the subject of the formula and find 'a' if the area of a hexagon is 54sqrt(3) sq. units.
