`Y = 5sin(3omegat + phi)` where `omega` and`phi` are constant. Finf `dy/dx`

If y=2sin(omegat+phi) where omega and phi constants then (dy)/(dt) will be

If y=2sin(omegat+phi) where omega and phi constants then (dy)/(dt) will be

y(xt)=asin(kx-omegat+phi) represents a

y(xt)=asin(kx-omegat+phi) represents a

The displacement in simple harmonic motion can be represented as x(t)=Acos(omegat + phi) ,where phi is the phase constant. Define A in the equation.

Find cos( theta + phi) " where " theta " and " phi " are acute angles and " sin theta = 4/5 " and " sin phi = 3/5.

The effects are produced at a given point in space by two wave decribed by the equations y_(1) = y_(m) sin omegat and y_(2) = y_(m) sin (omegat + phi) where y_(m) is the same for both the waves and phi is a phase angle. Tick the incorrect statement among the following.

Check the correctness of the equation : y = a "sin" (omega t + phi) , where y = displacement , a = amplitude , omega = angular frequency and phi is an angle .